30+ Abaxis Aptitude Interview Questions And Answers

Spread the love

Abaxis Aptitude Interview Questions

Q 1. P Is Able To Do A Piece Of Work In 15 Days And Q Can Do The Same Work In 20 Days. If They Can Work Together For 4 Days, What Is The Fraction Of Work Left ?

Amount of labor P can do in 1 day = 1/15

Amount of labor Q can do in 1 day = 1/20

Amount of labor P and Q can do in 1 day = 1/15 + 1/20 = 7/60

Amount of labor P and Q can collectively do in Four days = 4 × (7/60) = 7/15

Fraction of labor left = 1 – 7/15= 8/15

Q 2. P Can Lay Railway Track Between Two Stations In 16 Days. Q Can Do The Same Job In 12 Days. With The Help Of R, They Completes The Job In 4 Days. How Much Days Does It Take For R Alone To Complete The Work ?

Amount of labor P can do in 1 day = 1/16

Amount of labor Q can do in 1 day = 1/12

Amount of labor P, Q and R can collectively do in 1 day = 1/4

Amount of labor R can do in 1 day = 1/4 – (1/16 + 1/12) = 3/16 – 1/12 = 5/48

=> Hence R can do the job on 48/5 days = 9 (3/5) days

Q 3. P, Q And R Can Do A Work In 20, 30 And 60 Days Respectively. How Many Days Does It Need To Complete The Work If P Does The Work And He Is Assisted By Q And R On Every Third Day?

Amount of labor P can do in 1 day = 1/20

Amount of labor Q can do in 1 day = 1/30

Amount of labor R can do in 1 day = 1/60

P is working alone and each third day Q and R helps him

Work accomplished in each three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5

So work accomplished in 15 days = 5 × 1/5 = 1

Ie, the work might be accomplished in 15 days

Q 4. A Is Thrice As Good As B In Work. A Is Able To Finish A Job In 60 Days Less Than B. They Can Finish The Work In – Days If They Work Together.

If A completes a piece in 1 day, B completes the identical work in Three days

Hence, if the distinction is 2 days, B can full the work in Three days

=> if the distinction is 60 days, B can full the work in 90 days

=> Amount of labor B can do in 1 day= 1/90

Amount of labor A can do in 1 day = 3 × (1/90) = 1/30

Amount of labor A and B can collectively do in 1 day = 1/90 + 1/30 = 4/90 = 2/45

=> A and B collectively can do the work in 45/2 days = 221/2 days

Q 5. A Can Do A Particular Work In 6 Days . B Can Do The Same Work In 8 Days. A And B Signed To Do It For Rs. 3200. They Completed The Work In 3 Days With The Help Of C. How Much Is To Be Paid To C ?

Amount of labor A can do in 1 day = 1/6

Amount of labor B can do in 1 day = 1/8

Amount of labor A + B can do in 1 day = 1/6 + 1/8 = 7/24

Amount of labor A + B + C can do = 1/3

Amount of labor C can do in 1 day = 1/3 – 7/24 = 1/24

work A can do in 1 day: work B can do in 1 day: work C can do in 1 day

= 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Amount to be paid to C = 3200 × (1/8) = 400

Q 6. 6 Men And 8 Women Can Complete A Work In 10 Days. 26 Men And 48 Women Can Finish The Same Work In 2 Days. 15 Men And 20 Women Can Do The Same Work In – Days.

Let work accomplished by 1 man in 1 day = m and work accomplished by 1 girl in 1 day = b

Work accomplished by 6 males and eight ladies in 1 day = 1/10

=> 6m + 8b = 1/10

=> 60m + 80b = 1 — (1)

Work accomplished by 26 males and 48 ladies in 1 day = half

=> 26m + 48b = ½

=> 52m + 96b = 1— (2)

Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200

Work accomplished by 15 males and 20 ladies in 1 day

= 15/100 + 20/200 =1/4

=> Time taken by 15 males and 20 ladies in doing the work = Four days

Q 7. A Can Do A Piece Of Work In 4 Hours . A And C Together Can Do It In Just 2 Hours, While B And C Together Need 3 Hours To Finish The Same Work. B Alone Can Complete The Work In — Hours.

Work accomplished by A in 1 hour = 1/4

Work accomplished by B and C in 1 hour = 1/3

Work accomplished by A and C in 1 hour = half

Work accomplished by A,B and C in 1 hour = 1/4+1/3 = 7/12

Work accomplished by B in 1 hour = 7/12 – half = 1/12 => B alone can full the work in 12 hours.

Q 8. P Can Do A Work In The Same Time In Which Q And R Together Can Do It. If P And Q Work Together, The Work Can Be Completed In 10 Days. R Alone Needs 50 Days To Complete The Same Work. Then Q Alone Can Do It In

Work accomplished by P and Q in 1 day = 1/10

Work accomplished by R in 1 day = 1/50

Work accomplished by P, Q and R in 1 day = 1/10 + 1/50 = 6/50

But Work accomplished by P in 1 day = Work accomplished by Q and R in 1 day . Hence the above equation may be written as

Work accomplished by P in 1 day × 2 = 6/50

=> Work accomplished by P in 1 day = 3/50

=> Work accomplished by Q and R in 1 day = 3/50

Hence work accomplished by Q in 1 day = 3/50 – 1/50 = 2/50 = 1/25

So Q alone can do the work in 25 days.

Q 9. A Completes 80% Of A Work In 20 Days. Then B Also Joins And A And B Together Finish The Remaining Work In 3 Days. How Long Does It Need For B If He Alone Completes The Work?

Work accomplished by A in 20 days = 80/100 = 8/10 = 4/5

Work accomplished by A in 1 day = (4/5) / 20 = 4/100 = 1/25 — (1)

Work accomplished by A and B in Three days = 20/100 = 1/5 (Because remaining 20% is finished in Three days by A and B)

Work accomplished by A and B in 1 day = 1/15 —(2)

Work accomplished by B in 1 day = 1/15 – 1/25 = 2/75

=> B can full the work in 75/2 days = 37 half days

Q 10. Machine P Can Print One Lakh Books In 8 Hours. Machine Q Can Print The Same Number Of Books In 10 Hours While Machine R Can Print The Same In 12 Hours. All The Machines Started Printing At 9 A.m. Machine P Is Stopped At 11 A.m. And The Remaining Two Machines Complete Work. Approximately At What Time Will The Printing Of One Lakh Books Be Completed ?

Work accomplished by P in 1 hour = 1/8

Work accomplished by Q in 1 hour = 1/10

Work accomplished by R in 1 hour = 1/12

Work accomplished by P,Q and R in 1 hour = 1/8 + 1/10 + 1/12 = 37/120

Work accomplished by Q and R in 1 hour = 1/10 + 1/12 = 22/120 = 11/60

From 9 am to 11 am, all of the machines have been working.

Ie, all of them operated for two hours and work accomplished = 2 × (37/120) = 37/60

Pending work = 1- 37/60 = 23/60

Hours taken by Q an R to finish the pending work = (23/60) / (11/60) = 23/11 which is roughly equal to 2 Hence the work might be accomplished roughly 2 hours after 11 am ; ie round 1 pm

Q 11. P Can Finish A Work In 18 Days. Q Can Finish The Same Work In 15 Days. Q Worked For 10 Days And Left The Job. How Many Days Does P Alone Need To Finish The Remaining Work ?

Work accomplished by P in 1 day = 1/18

Work accomplished by Q in 1 day = 1/15

Work accomplished by Q in 10 days = 10/15 = 2/3

Remaining work = 1 – 2/3 = 1/3

Number of days through which P can end the remaining work = (1/3) / (1/18) = 6

Q 12. 3 Men And 7 Women Can Complete A Work In 10 Days . But 4 Men And 6 Women Need 8 Days To Complete The Same Work . In How Many Days Will 10 Women Complete The Same Work ?

Work accomplished by Four males and 6 ladies in 1 day = 1/8

Work accomplished by Three males and seven ladies in 1 day = 1/10

Let 1 man does m work in 1 day and 1 girl does w work in 1 day. The above equations may be written as

4m + 6w = 1/8 —(1)

3m + 7w = 1/10 —(2)

Solving equation (1) and (2) , we get m=11/400 and w=1/400

Amount of labor 10 ladies can do in a day = 10 × (1/400) = 1/40

Ie, 10 ladies can full the work in 40 days

Q 13. A And B Can Finish A Work 30 Days If They Work Together. They Worked Together For 20 Days And Then B Left. A Finished The Remaining Work In Another 20 Days. In How Many Days A Alone Can Finish The Work ?

Amount of labor accomplished by A and B in 1 day = 1/30

Amount of labor accomplished by A and B in 20 days = 20 × (1/30) = 20/30 = 2/3

Remaining work – 1 – 2/3 = 1/3

A completes 1/Three work in 20 days

Amount of labor A can do in 1 day = (1/3)/20 = 1/60

=> A can full the work in 60 days

Q 14. A Can Complete A Work In 12 Days With A Working Of 8 Hours Per Day. B Can Complete The Same Work In 8 Days When Working 10 Hours A Day. If A And B Work Together, Working 8 Hours A Day, The Work Can Be Completed In — Days.

A can full the work in 12 days working Eight hours a day

=> Number of hours A can full the work = 12×8 = 96 hours

=> Work accomplished by A in 1 hour = 1/96

B can full the work in Eight days working 10 hours a day

=> Number of hours B can full the work = 8×10 = 80 hours

=> Work accomplished by B in 1 hour = 1/80

Work accomplished by A and B in 1 hour = 1/96 + 1/80 = 11/480

=> A and B can full the work in 480/11 hours

A and B works Eight hours a day

Hence complete days to finish the work with A and B working collectively

= (480/11)/ (8) = 60/11 days = 5 5/11 days

Q 15. P Is 30% More Efficient Than Q. P Can Complete A Work In 23 Days. If P And Q Work Together, How Much Time Will It Take To Complete The Same Work ?

Work accomplished by P in 1 day = 1/23

Let work accomplished by Q in 1 day = q

q × (130/100) = 1/23

=> q = 100/(23×130) = 10/(23×13)

Work accomplished by P and Q in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13

=> P and Q collectively can do the work in 13 days

Q 16. P, Q And R Can Complete A Work In 24, 6 And 12 Days Respectively. The Work Will Be Completed In — Days If All Of Them Are Working Together.

Work accomplished by P in 1 day = 1/24

Work accomplished by Q in 1 day = 1/6

Work accomplished by R in 1 day = 1/12

Work accomplished by P,Q and R in 1 day = 1/24 + 1/6 + 1/12 = 7/24

=> Working collectively, they may full the work in 24/7 days = Three 3/7 days

Q 17. 10 Men Can Complete A Work In 7 Days. But 10 Women Need 14 Days To Complete The Same Work. How Many Days Will 5 Men And 10 Women Need To Complete The Work ?

Work accomplished by 10 males in 1 day = 1/7

Work accomplished by 1 man in 1 day = (1/7)/10 = 1/70

Work accomplished by 10 ladies in 1 day = 1/14

Work accomplished by 1 girl in 1 day = 1/140

Work accomplished by 5 males and 10 ladies in 1 day = 5 × (1/70) + 10 × (1/140)

= 5/70 + 10/140 = 1/7

=> 5 males and 10 ladies can full the work in 7 days

Q 18. Kamal Will Complete Work In 20 Days. If Suresh Is 25% More Efficient Than Kamal, He Can Complete The Work In — Days.

Work accomplished by Kamal in 1 day = 1/20

Work accomplished by Suresh in 1 day = (1/20) × (125/100) = 5/80 = 1/16

=> Suresh can full the work in 16 days

Q 19. Anil And Suresh Are Working On A Special Assignment. Anil Needs 6 Hours To Type 32 Pages On A Computer And Suresh Needs 5 Hours To Type 40 Pages. If Both Of Them Work Together On Two Different Computers, How Much Time Is Needed To Type An Assignment Of 110 Pages ?

Pages typed by Anil in 1 hour = 32/6 = 16/3

Pages typed by Suresh in 1 hour = 40/5 = 8

Pages typed by Anil and Suresh in 1 hour = 16/3 + 8 = 40/3

Time taken to kind 110 pages when Anil and Suresh work collectively = 110 × 3 /40 = 33/4

= Eight 1/Four hours = Eight hour 15 minutes

Q 20. P And Q Can Complete A Work In 20 Days And 12 Days Respectively. P Alone Started The Work And Q Joined Him After 4 Days Till The Completion Of The Work. How Long Did The Work Last ?

Work accomplished by P in 1 day = 1/20

Work accomplished by Q in 1 day = 1/12

Work accomplished by P in Four days = 4 × (1/20) = 1/5

Remaining work = 1 – 1/5 = 4/5

Work accomplished by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15

Number of days P and Q take to finish the remaining work = (4/5) / (2/15) = 6

Total days = 4 + 6 = 10

Q 21. P Takes Twice As Much Time As Q Or Thrice As Much Time As R To Finish A Piece Of Work. They Can Finish The Work In 2 Days If Work Together. How Much Time Will Q Take To Do The Work Alone ?

Let P takes x days to finish the work

Then Q takes x/2 days and R takes x/Three days to complete the work

Amount of labor P does in 1 day = 1/x

Amount of labor Q does in 1 day = 2/x

Amount of labor R does in 1 day = 3/x

Amount of labor P,Q and R do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x

6/x = 2

=> x = 12

=> Q takes 12/2 days = 6 days to finish the work.

Q 22. P And Q Can Complete A Work In 15 Days And 10 Days Respectively. They Started The Work Together And Then Q Left After 2 Days. P Alone Completed The Remaining Work. The Work Was Finished In — Days.

Work accomplished by P in 1 day = 1/15

Work accomplished by Q in 1 day = 1/10

Work accomplished by P and Q in 1 day = 1/15 + 1/10 = 1/6

Work accomplished by P and Q in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3

Time taken by P to finish the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

Q 23. P And Q Can Do A Work In 30 Days. Q And R Can Do The Same Work In 24 Days And R And P In 20 Days. They Started The Work Together, But Q And R Left After 10 Days. How Many Days More Will P Take To Finish The Work ?

Let work accomplished by P in 1 day = p,

Work accomplished by Q in 1 day = q,

Work accomplished by R in 1 day = r

p + q = 1/30

q + r = 1/24

r + p = 1/20

Adding all of the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8

=> p + q + r = 1/16

=> Work accomplished by P,Q and R in 1 day = 1/16

Work accomplished by P, Q and R in 10 days = 10 × (1/16) = 10/16 = 5/8

Remaining work = 1 = 5/8 = 3/8

Work accomplished by P in 1 day = Work accomplished by P,Q and R in 1 day – Work accomplished by Q and R in 1 day

= 1/16 – 1/24 = 1/48

Number of days P must work to finish the remaining work = (3/8) / (1/48) = 18

Q 24. P Works Twice As Fast As Q. If Q Alone Can Complete A Work In 12 Days, P And Q Can Finish The Work In — Days

Work accomplished by Q in 1 day = 1/12

Work accomplished by P in 1 day = 2 × (1/12) = 1/6

Work accomplished by P and Q in 1 day = 1/12 + 1/6 = ¼

=> P and Q can end the work in Four days

Q 25. A Work Can Be Finished In 16 Days By Twenty Women. The Same Work Can Be Finished In Fifteen Days By Sixteen Men. The Ratio Between The Capacity Of A Man And A Woman Is

Work accomplished by 20 ladies in 1 day = 1/16

Work accomplished by 1 girl in 1 day = 1/(16×20)

Work accomplished by 16 males in 1 day = 1/15

Work accomplished by 1 man in 1 day = 1/(15×16)

Ratio of the capability of a person and girl =1/(15×16) : 1/(16×20) = 1/15 : 1/20

= 1/3 :1/4 = 4:3

Q 26. P And Q Need 8 Days To Complete A Work. Q And R Need 12 Days To Complete The Same Work. But P, Q And R Together Can Finish It In 6 Days. How Many Days Will Be Needed If P And R Together Do It ?

Let work accomplished by P in 1 day = p

work accomplished by Q in 1 day =q

Work accomplished by R in 1 day = r

p + q = 1/8 —(1)

q + r= 1/12 —(2)

p+ q+ r = 1/6 —(3)

(3) – (2) => p = 1/6 – 1/12 = 1/12

(3) – (1) => r = 1/6 – 1/8 = 1/24

p + r = 1/12 + 1/24 = 3/24 = 1/8

=> P and R will end the work in Eight days

Q 27. P Can Do A Work In 24 Days. Q Can Do The Same Work In 9 Days And R Can Do The Same In 12 Days. Q And R Start The Work And Leave After 3 Days. P Finishes The Remaining Work In — Days.

Work accomplished by P in 1 day = 1/24

Work accomplished by Q in 1 day = 1/9

Work accomplished by R in 1 day = 1/12

Work accomplished by Q and R in 1 day = 1/9 + 1/12 = 7/36

Work accomplished by Q and R in Three days = 3×7/36 = 7/12

Remaining work = 1 – 7/12 = 5/12

Number of days through which P can end the remaining work = (5/12) / (1/24) = 10

Q 28. If Daily Wages Of A Man Is Double To That Of A Woman, How Many Men Should Work For 25 Days To Earn Rs.14400? Given That Wages For 40 Women For 30 Days Are Rs.21600.

Wages of 1 girl for 1 day = 2160040×30

Wages of 1 man for 1 day = 21600×240×30

Wages of 1 man for 25 days = 21600×2×2540×30

Number of males = 14400(21600×2×2540×30)=144(216×5040×30)=1449=16

Q 29. P,q And R Together Earn Rs.1620 In 9 Days. P And R Can Earn Rs.600 In 5 Days. Q And R In 7 Days Can Earn Rs.910. How Much Amount Does R Can Earn Per Day ?

Amount Earned by P,Q and R in 1 day = 1620/9 = 180 —(1)

Amount Earned by P and R in 1 day = 600/5 = 120 —(2)

Amount Earned by Q and R in 1 day = 910/7 = 130 —(3)

(2)+(3)-(1) => Amount Earned by P , Q and 2R in 1 day

– Amount Earned by P,Q and R in 1 day = 120+130-180 = 70

=>Amount Earned by R in 1 day = 70

Q 30. Assume That 20 Cows And 40 Goats Can Be Kept For 10 Days For Rs.460. If The Cost Of Keeping 5 Goats Is The Same As The Cost Of Keeping 1 Cow, What Will Be The Cost For Keeping 50 Cows And 30 Goats For 12 Days ?

Assume that value of maintaining a cow for 1 day = c ,

value of maintaining a goat for 1 day = g

Cost of maintaining 20 cows and 40 goats for 10 days = 460

Cost of maintaining 20 cows and 40 goats for 1 day = 460/10 = 46

=> 20c + 40g = 46

=> 10c + 20g = 23 —(1)

Given that 5g = c

Hence equation (1) may be written as 10c + 4c = 23 => 14c =23

=> c=23/14

value of maintaining 50 cows and 30 goats for 1 day

= 50c + 30g

= 50c + 6c (substituted 5g = c)

= 56 c = 56×23/14

= 92

Cost of maintaining 50 cows and 30 goats for 12 days = 12×92 = 1104

Q 31. There Is A Group Of Persons Each Of Whom Can Complete A Piece Of Work In 16 Days, When They Are Working Individually. On The First Day One Person Works, On The Second Day Another Person Joins Him, On The Third Day One More Person Joins Them And This Process Continues Till The Work Is Completed. How Many Days Are Needed To Complete The Work?

Work accomplished in 1st day = 1/16

Work accomplished in 2nd day = (1/16) + (1/16) = 2/16

Work accomplished in third day = (1/16) + (1/16) + (1/16) = 3/16


Spread the love